Answered

What is the volume of the gas if there are 3.20 mol of gas at 265 K and 2.50 atm of pressure?

Answer :

MAACASTROBRGO

Answer:

27.81 L

Explanation:

Assuming the gas is ideal, we can solve this problem by using the following formula:

  • PV = nRT

Where:

  • P is Pressure, 2.50 atm
  • V is Volume
  • n is the number of moles, 3.20 mol
  • R is a constant, 0.082 atm·L·mol⁻¹·K⁻¹
  • T is temperature, 265 K

We input the data:

  • 2.50 atm * V = 3.20 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 265 K

And solve for V:

  • V = 27.81 L

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