Juanita is a 28-year old female college graduate from the South. Molly is a 28-year female college graduate from the West. Jennifer is a 28-year female college graduate from the Midwest. (i) Construct a 95% confidence interval for the difference in expected earnings between Juanita and Molly. (ii) Explain how you would construct a 95% confidence interval for the difference in expected earnings between Juanita and Jennifer.

Answer :

Answer:

Hello your question has some missing information attached below is the missing information

answer :

i) ( 0.158 , - 1.018 )

ii)  the difference in expected earnings can be computed as

( [tex]X_{6,A} - X_{5,C} ) = \beta _{0} + \beta _{6} - ( \beta _{0} - \beta _{5} ) = \beta _{6} - \beta _{5}[/tex]

Step-by-step explanation:

i) Construct a 95% confidence interval ( between Juanita and Molly )

Expected difference in earnings = ( X[tex]_{6}[/tex][tex]_{,A}[/tex] - X[tex]_{6.B}[/tex]) = [tex]\beta _{0}[/tex]= ( [tex]\beta + \beta _{6}[/tex] )

∴ 95% confidence interval

-0.43 ± 1.96 * 0.30 = [ -0.43 ± 0.588 ] =  ( 0.158 , - 1.018 )  ( hence confidence interval at 95% = 1.96 )

ii) Construct a 95% confidence interval ( between Juanita and Jennifer )

Juanita is a student from the south and Jennifer is a student from Midwest

therefore the difference in expected earnings can be computed as

( [tex]X_{6,A} - X_{5,C} ) = \beta _{0} + \beta _{6} - ( \beta _{0} - \beta _{5} ) = \beta _{6} - \beta _{5}[/tex]

therefore a 95% confidence interval can be calculated with the above regression model.

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