The value of g(3.5) is 41.49 to the nearest hundredth
Exponential function
The standard exponential function is given as g(x) = ab^x
If g(-2.5) = 9 and g(2.5) = 45, hence;
9 = ab^-2.5 .............. 1
45 = ab^2.5 .............2
Divide both equations:
9/45 = b^{-2.5-2.5}
1.5 = b^-5
1.5= 1/b^5
b^5 = 0.6666
b = 0.922
Also since 45 = ab^2.5 .
45 = a(0.922)^2.5
45 = 0.81625a
a = 55.13
g(3.5) = 55.13(0.922)^3.5
g(3.5) = 41.49
Hence the value of g(3.5) is 41.49 to the nearest hundredth
Learn more on exponential function here: https://brainly.com/question/12940982
