Answer:
see explanation
Step-by-step explanation:
(a)
Given
[tex]\frac{y}{3}[/tex] + [tex]\frac{y+3}{5}[/tex]
The common denominator is 15 ( the LCM of 3 and 5 )
Multiply numerator/ denominator of first fraction by 5
Multiply the numerator/ denominator of second fraction by 3
= [tex]\frac{5y}{15}[/tex] + [tex]\frac{3y+9}{15}[/tex] ← add numerators , leaving denominator of 15
= [tex]\frac{5y+3y+9}{15}[/tex]
= [tex]\frac{8y+9}{15}[/tex]
(b)
Given
[tex]\frac{3x}{8}[/tex] - [tex]\frac{x+5}{4}[/tex]
The common denominator is 8 ( the LCM of 8 and 4 )
Multiply numerator/ denominator of second fraction by 2
= [tex]\frac{3x}{8}[/tex] - [tex]\frac{2(x+5)}{8}[/tex] ← simplify numerators leaving denominator of 8
= [tex]\frac{3x-2x-10}{8}[/tex]
= [tex]\frac{x-10}{8}[/tex]