Answer:
Sam's average velocity for the entire walk is approximately;
0.075 km/min
Explanation:
The given parameters of the Lake Loop Trail are;
The distance of the trail Sam takes his dog to walk around = 5-km
From the table for the position and time, we have;
[tex]\begin{array}{ccc}Position \ (km) &&Time \ (min)\\0&&0\\1&&12\\2&&22\\3&&33\\4&&54\\5&&67\end{array}[/tex]
Plotting the given points gives the attached chart created with Microsoft Excel
The coordinates of the points are A(0,0), B(67, 5), C(67, 0)
By the definition of average velocity, we have;
[tex]Average \ velocity = \dfrac{Total \ distance}{Total \ time \ taken}[/tex]
From the plot of the points therefore, we have;
[tex]Average \ velocity= \dfrac{Length \ of BC}{The \ time \ elapsed \ between \ AC} = \dfrac{5 \ km - 0 \ km}{67 \ min - 0 \ min} = \dfrac{5 \ km}{67 \ min} \approx 0.075 \ km/min[/tex]Therefore;
Sam walked at an average velocity of approximately 0.075 km/min.
