Atomic mass of Sulfur = 32g
32g of Sulfur is one mole.
1g of Sulfur is [tex] \frac{1}{32} moles [/tex]
96.21g of Sulfur is [tex] \frac{96.21}{32} moles=> 3moles(appx) [/tex]
Answer:
[tex]\boxed {\boxed {\sf 3 \ moles \ sulfur}}[/tex]
Explanation:
To convert from grams to moles, the molar mass is used. This value is the number of grams in 1 mole of a substance and it can be found on the Periodic Table. Look for Sulfur or S.
We use this as a ratio.
[tex]\frac {32.07 \ g \ S}{1 \ mo;\l\ S }[/tex]
Multiply by the given number of grams.
[tex]96.21 \ g \ S*\frac {32.07 \ g \ S}{1 \ mo\l\ S }[/tex]
Flip the fraction so the grams of sulfur cancel out.
[tex]96.21 \ g \ S*\frac {1 \ mol \ S}{32.07 \ g \ S }[/tex]
[tex]96.21*\frac {1 \ mol \ S}{32.07 }[/tex]
[tex]\frac {96.21 \ mol \ S}{32.07 }= 3 \ mol \ S[/tex]
96.21 grams of sulfur is equal to 3 moles of sulfur.
