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A tennis ball with mass 57 g is travelling at 25 m/s [S] when it is intercepted by a tennis racquet for 4.0 ms after which the ball travels at 32 m/s [N]. What is the average force applied to the ball by the racquet?

Answer :

Answer:

F = 812.25 N

Explanation:

Given (convert to SI units):

m = 57 g = 0.057 kg

[tex]v_{1}[/tex] = -25 [tex]\frac{m}{s}[/tex]

[tex]v_{2}[/tex] = 32 [tex]\frac{m}{s}[/tex]

t = 4 ms = 0.004 s

Find acceleration:

a = [tex]\frac{v_{2}-v_{1} }{t}[/tex] = [tex]\frac{32-(-25)}{0.004}[/tex] = 14250

Find force:

F = ma = 0.057(14250) = 812.25 N

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