Question: The graph of a second-order polynomial is shown below, and the intercepts with the axes are marked. Explain how you can use the graph to write the polynomial as a product of linear factors (x-a)(x-b). Be sure to state the values of a and b. NEED HELP ASAP​

Question The Graph Of A Secondorder Polynomial Is Shown Below And The Intercepts With The Axes Are Marked Explain How You Can Use The Graph To Write The Polynom class=

Answer :

Hello!

Here we are given a second-order polynomial, and the root form of the function.

[tex]y=a(x-c)(x-d)[/tex]

Where c and d are zeros of the function, which is where the graph intersects the x-axis.

[tex]y=a(x+4)(x-3)[/tex]

[tex]-6=a(2+4)(2-3)[/tex]

[tex]-6=-6a[/tex]

[tex]a=1[/tex]

Therefore, the equation of this polynomial would be [tex]y=(x+4)(x-3)[/tex], and the values of a and b would be the x-intercepts.

Hope this helps!