What is the value of the equilibrium constant K ?

Answer:
K = 0.0209
Explanation:
K = [tex]\frac{[H_{2}][I_{2}]}{[2HI]^{2}}[/tex]
K = [tex]\frac{[4.35 x 10^{-2} ][2.79 x 10^{-2} ]}{[0.241]^{2} }[/tex]
K = 0.0208958
K = 0.0209