Answer :
Answer:
[tex]d=1.78\times 10^{-7}\ Dg/\mu m^3[/tex]
Explanation:
Given,
The density of Helium is [tex]1.78\times 10^4\ g/cm^3[/tex]
We need to find the density in Dg/μm
We know that,
1 g = 10 dg
1 cm³ = 10¹² μm³
So,
[tex]d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3[/tex]
So, the density of Helium is equal to [tex]1.78\times 10^{-7}\ Dg/\mu m^3[/tex].