Similar triangles may or may not be congruent triangles.
The true statement is (d) ∠DCE is congruent to ∠CBA by the Vertical Angles Theorem and 15 over 5 equals 12 over 4 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SSS Similarity Postulate.
From the figure, we have the following corresponding sides:
- AB and DE
- AC and CE
- BC and DC
The means that, the following equivalent ratio (k) is true
[tex]\mathbf{k =\frac{DE}{AB} = \frac{CE}{AC} = \frac{DC}{BC}}[/tex]
So, we have:
[tex]\mathbf{k =\frac{9}{3} = \frac{12}{4} = \frac{15}{5}}[/tex]
The above gives
[tex]\mathbf{k =3}[/tex]
This means that, the triangles are similar by SSS postulate (all three sides are corresponding).
And ∠DCE and ∠CBA are congruent by vertical angles theorem.
Hence, the true statement is: (d)
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