Answer:
[tex]P(A) = \frac{3}{10}[/tex]
Step-by-step explanation:
Given
[tex]S = \{11,12,13,14,15,16,17,18,19,20\}[/tex]
Required
The probability of having a multiple of 3
Let the event of having a multiple of 3 be represented as: A
So:
[tex]A = \{12,15,18\}[/tex]
[tex]n(A) = 3[/tex]
So, the probability is:
[tex]P(A) = \frac{n(A)}{n(S)}[/tex]
Where
[tex]n(S) = 10[/tex] i.e. the sample size
So:
[tex]P(A) = \frac{n(A)}{n(S)}[/tex]
[tex]P(A) = \frac{3}{10}[/tex]
