MATTMARTIN2003GO
Answered

Hi can someone please help me with this question I've been stuck on it for soooo long!!

Hi Can Someone Please Help Me With This Question Ive Been Stuck On It For Soooo Long class=

Answer :

CAIRDEGO

Answer:

Let x=sinθ

2sin²θ = 5sinθ - 3

2x²=5x-3

2x²-5x+3=0

(2x-3)(x-1)=0

2x-3=0 or x-1=0

x=3/2 or x=1

sinθ=2/3 or sinθ=1

θ=arcsin(2/3) or θ=arcsin(1)

θ=0.729727656 or θ=1.57079633=π/2

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