Answer:
Solution given:
we have
<A+<B=exterior <C[sum of two opposite interior angle of a triangle is equal to the exterior angle in a triangle]
So
3x-13+ 2x+4=116°
5x-9=116°
5x=116°+9°
x=125/5
x=25
Now
<A=3×25-13=62°
<B=2×25+4=54°
[tex]3x - 13 + 2x + 4 = 166 \\ 5x - 9 = 116 \\ 5x = 166 + 9 \\ 5x = 125 \\ x = \frac{125}{5} \\ x = 25 \\ \\ a = 3 \times 25 - 13 = 62 \\ b = 2 \times 25 + 4 = 54[/tex]
