What is the volume of .80 g of O2 gas at STP?

Answer :

Answer:

80g of O2 will contain = (1/16)*80=5 moles

Explanation:

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To find the number of grams 0.80 g of O2 has you must take the number of grams and divide it by the molar mass. The molar mass of O2 is 32.00.

0.80/32.00=0.025 mol

Now to convert this to liters at STP, you have to multiply that, by 22.4.

0.025*22.4=0.56 L