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Force of a Baseball Swing. A baseball has mass 0.153 kg . Part A If the velocity of a pitched ball has a magnitude of 44.5 m/s and the batted ball's velocity is 50.5 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. Express your answer to three significant figures and include the appropriate units. P

Answer :

Answer: 14.5 kg.m/s

Explanation:

Given

mass of baseball is [tex]m=0.153\ kg[/tex]

The initial speed of the ball is [tex]u=-44.5\ m/s[/tex]

the final speed of the ball is [tex]v=50.5\ m/s[/tex]

Impulse is given as a change in the momentum

[tex]\vec{J}=\Delta \vec{P}[/tex]

[tex]J=m(v-u)\\J=0.153(50.5-(44.5))\\J=0.153\times 95=14.535\ kg.m/s[/tex]

Change in momentum up to 3 significant figures is 14.5 kg.m/s

Impulse applied by a bat is also the same as the change in momentum

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