Answer :
Answer:
286.2 pa
Explanation:
Blood speed in a normal segment of a horizontal artery ( v2 ) = 0.15 m/s
Density of blood = 1060 kg/m^3
Normal sectional area = A2
constricted sectional area ( A1 )= 1/5 A2
Determine the difference in blood pressures between the normal and constricted segments
we will apply Equation of continuity Av = constant
Δ p = 12 PV^2
= 12 * 1060 * ( 0.15 )^2
= 12720 * 0.0225 = 286.2 pa
attached below is a detailed solution of the Given problem
