Answered

How much heat is required to raise the temperature of 250.0 g of mercury by 52 degrees * C with a specific heat of 4.18

Answer :

A3073703GO
Heat required = M * C * (delta T)
= (Mass)*(Specific heat)*(temperature change)
= 250 * 4.18* 52 = 54340Joules.

I solve when unit of specific heat is (J/gC) if have another unit please tell me
JCJEY1611GO

Answer:

250*4.18*52=54340

Explanation:

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