Step-by-step explanation:
Since this is a right triangle and we are given an angle measure that measure 45, the other angle measure also measure 45.
So this means we are dealing with a 45-45-90 triangle.
A 45-45-90 triangle legs are equal to each other and the hypotenuse measures sqr root of 2 times more than the legs.
The hypotenuse measure 2 times sqr root of 14 so divide by sqr root of 2 to find x and y.
[tex] \frac{2 \sqrt{14} }{1} \times \frac{1}{ \sqrt{2 } } = \frac{ \sqrt{56} }{ \sqrt{2} } = \sqrt{28} = 2 \sqrt{7} [/tex]
Since x and y are equal, they both measure
[tex]2 \sqrt{7} [/tex]
