Answered

488 nm light passes through a single
slit. The first (m = 1) diffraction
minimum occurs at an angle of
0.559º. What is the width of the slit?
[?] x 10-5 m

488 Nm Light Passes Through A Single Slit The First M 1 Diffraction Minimum Occurs At An Angle Of 0559º What Is The Width Of The Slit X 105 M class=

Answer :

Answer:

5.00

Explanation:

a sinθ=mλ

You are missing (a) so you move sinθ to the other side than solve from there.

For first diffraction, the width of the slit is [tex]5*10^{-5} m[/tex].

What is diffraction?

Diffraction of light is defined as the bending of light around corners such that it spreads out and illuminates areas where a shadow is expected.

a sinθ=mλ

[tex]a = \frac{1*488*10^{-9} }{sin 0.559}[/tex]

[tex]a = 5*10^{-5} m[/tex]

To learn more about Diffraction here

https://brainly.com/question/16096548

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