Answer:
[tex] m\angle AED=90\degree [/tex]
[tex] m\angle DAE=53\degree [/tex]
[tex] m\angle BCE= 53\degree [/tex]
Step-by-step explanation:
ABCD is a rhombus. AC and BD are its diagonals intersecting at point E.
Diagonals of a rhombus bisects at right angles.
[tex] \therefore m\angle AED=90\degree [/tex]
[tex] In\: \triangle AED[/tex]
[tex] m\angle DAE=90\degree-m\angle EDA [/tex]
[tex] m\angle DAE=90\degree-37\degree [/tex]
[tex] m\angle DAE=53\degree [/tex]
[tex] \because m\angle BCE= m\angle DAE [/tex]
(Alternate angles)
[tex] \therefore m\angle BCE= 53\degree [/tex]
