In a series circuit . . .
-- The total resistance is the sum of the individual resistors.
-- The current is the same at every point in the circuit.
The total resistance in this circuit is (3Ω + 6Ω ) = 9Ω
The current at every point is (V/R) = (12v / 9Ω ) = 1.33 A .
Pick choice (a).
The current flowing through the 6 Ohms resistor is: a. 1.33 A
Given the following data:
To find the current flowing through the 6 Ohms resistor:
First of all, we would determine the total equivalent resistance of the resistors connected in series.
[tex]T_eq = Resistor \; A + Resistor\; B\\\\T_eq = 3 + 6[/tex]
Total equivalent resistance = 9 Ohms
Note: The current flowing through both resistors are the same since they are connected in series.
From Ohm's law, we have:
[tex]Current = \frac{Voltage}{Resistor}\\\\Current = \frac{12}{9}[/tex]
Current = 1.33 Amperes
Therefore, the current flowing through the 6 Ohms resistor is 1.33 Amperes.
