The area of a trapezium is 512 cm², the distance between its parallel sides if the sum of the lengths of the parallel sides is 64 cm is

Answer :

Answer:

h = 16 cm

Step-by-step explanation:

Given that,

The area of a trapezium, A = 512 cm²

The sum of the length of the parallel sides = 64 cm

The area of a trapezium is given by :

[tex]A=\dfrac{1}{2}\times \text{sum of parallel sides}\times height\\\\h=\dfrac{2A}{Sum}\\\\=\dfrac{2\times 512}{64}\\\\=16\ cm[/tex]

So, the distance between the parallel sides is 16 cm.