Answer: the 100th term of the sequence =-273 (1)
Step-by-step explanation:
Since the first term = 222
and d (common difference )=-5 Then we are talking about an arithmetic progression
The nth term of an Arithmetic progression is given as
Tn=a + (n - 1)d
Therefore given that n =100
Tn=a + (n - 1)d = 222 +(100-1)-5
222+ (99)-5
222-495=-273
