RIMRAMGO
Answered

A 0.70kW vacuum cleaner is used for 20 minutes. How much energy does it use? Give your answer in
kWh to two decimal places.

Answer :

KRISHNAANIL38199GO

20 minutes = 20/60 = 0.33 hr

0.7 kw * 0.33 hr = 0.231 kWh = 0.23 kWh

Plz mark as Brill

Energy used will be 0.23 kWh

What is Energy ?

Energy is  the capacity of a physical system to do work . The standard unit of energy is Joule(J).

Energy = power * time

Given :

power = 0.70 kW

time = 20 minutes = 20 / 60 hour

Energy = ?

Energy  = 0.70 * (20/60)

              = 0.23 kWh

Energy used will be 0.23 kWh

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