Answer :
Answer:
(0,1),)(-1)
Step-by-step explanation:
[tex]y^2=2^x+x\\put x=0\\y^2=2^0+0=1+0=1\\y= \pm \sqrt{1} =\pm1[/tex]
so solutions are (0,1) and (0,-1)

Answer:
(0,1),)(-1)
Step-by-step explanation:
[tex]y^2=2^x+x\\put x=0\\y^2=2^0+0=1+0=1\\y= \pm \sqrt{1} =\pm1[/tex]
so solutions are (0,1) and (0,-1)