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Plz help meh
A creature on the moon throws a rock off a cliff. The height of the rock above the surface of the moon, in meters, t seconds after it is thrown is given by h(t) = -t^2 + 8t + 10. When does the rock hit the surface of the moon?
Plz give step by step solution.

Answer :

IRSPOWGO

Answer:

Step-by-step explanation:

The rock will hit the surface when its height equals zero.

t^2-8t-10=0

t^2-8t=10

t^2-8t+16=10+16

(t-4)^2=26

t-4=+(26^(1/2))

t=4+(26^(1/2))

t=9.1s

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