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A 0.5 kg baseball is hit by a bat delivering an impulse of 180 kg x m/s. If the bat is in contact with the baseball for 0.4 seconds, what is the force delivered by the bat?

Answer :

OVERPOWEREDNOOBGO

Answer:

450N

Explanation:

Impulse = mv    --->   180kgm/s = (0.5kg)v

v = 360 m/s

Acceleration = v/t    --->   a = (360 m/s)/(0.4s) = 900 m/s^2

Force = ma   --->   F = (0.5kg)(900 m/s^2) = 450N

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