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A cricket player hit a ball of mass 250 g moving with velocity of 6 m/sec. if ball move with a velocity of 9 m/sec in opposite direction.
a. Calculate impulse of the system.
b. Deduce the force acting on it for 0.5 min

please someone answer

Answer :

Explanation:

Given that,

Mass of a ball, m = 250 g = 0.25 kg

Initial velocity of the ball, u = 6 m/s

Final velocity of the ball, v = -9 m/s

(a) Impulse of the system is given by :

Impulse = change in momentum

J = m(v-u)

J = 0.25(-9-6)

= -3.75 kg-m/s

(b) Impulse = Ft

If t = 0.5 min = 30 s

So,

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{-3.75}{30}\\\\F=-0.125\ N[/tex]

So, impulse of the system is -3.75 kg-m/s and the force is -0.125 N.

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