Answer:
x = 4cos(t) – 1 and y = 4sin(t) + 3
Step-by-step explanation:
Equation of a circle:
The equation of a circle has the following format:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
In which:
The centre is is [tex](x_0,y_0)[/tex] and r is the radius. The parametric equations are given by:
[tex]x(t) = r\cos{(t)} + x_0[/tex]
[tex]y(t) = r\sin{(t)} + y_0[/tex]
In this question:
[tex](x + 1)^2 + (y - 3)^2 = 4^2[/tex]
This means that the centre is [tex](-1,3)[/tex] and the radius is 4. So, the answer is:
x = 4cos(t) – 1 and y = 4sin(t) + 3
