Answer:
225 grams
Explanation:
Given: K + Cl₂ => 2KCl
excess 106.35g ?grams
Suggestion: For stoichiometry problems, convert all data given to moles and solve by ratio based on given equation and relative data given. After working in terms of moles, convert to dimension specified in problem.
moles Cl₂ = 106.35g / 70g/mol = 1.52 moles
From balanced equation:
1mol Cl₂ => 2mol KCl
1.52 mol Cl₂ => ?(mol KCl)
∴moles KCl produced = 2 mol KCl x 1.52 mol Cl₂ / 1 mol Cl₂ = 3.04 mol KCl
Grams KCl = 3.04 mole x 74 grams/mole = 225 grams
