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One football and two basketballs cost $92.00. Three basketballs and four footballs cost $212.00. Which system of equations could be used to find the costs of one basketball, b, and one football, f?

Answer :

DEBMC7GO
f + 2b = 92
3b + 4f = 212

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You didn’t say you need them solved, but just in case:

f = 92 -2b

3b + 4(92-2b) = 212
3b + 368 -8b = 212
-5b = -156
b = 31.20

f + 2(31.20) = 92
f + 62.4 = 92
f = 29.60

3(31.2) + 4(29.6) = 93.6 + 118.4 = 212

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