Answer:
[tex]g(-2) = 25[/tex]
[tex]g(-1) = 5[/tex]
[tex]g(0) = 1[/tex]
[tex]g(1) = \frac{1}{5}[/tex]
Step-by-step explanation:
Given
[tex]g(x) = \frac{1}{5}^x[/tex]
Solving (a): When x = -2
This gives:
[tex]g(x) = \frac{1}{5}^{(-2)[/tex]
[tex]g(x) = \frac{1}{5}^{-2[/tex]
[tex]g(x) = 5^2[/tex]
[tex]g(-2) = 25[/tex]
Solving (b) When x = -1
This gives:
[tex]g(x) = \frac{1}{5}^{-1}[/tex]
[tex]g(-1) = 5[/tex]
When x = 0
This gives:
[tex]g(x) = \frac{1}{5}^0[/tex]
[tex]g(0) = 1[/tex]
When x = 1
This gives:
[tex]g(x) = \frac{1}{5}^1[/tex]
[tex]g(1) = \frac{1}{5}[/tex]