Answer:
[tex]\boxed {\boxed {\sf 56 \ Joules}}[/tex]
Explanation:
We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.
[tex]q=mc \Delta T[/tex]
The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.
- ΔT= final temperature - initial temperature
- ΔT= 95°C - 15°C = 80°C
We know the variables and can substitute them into the formula.
[tex]m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C[/tex]
[tex]q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)[/tex]
Multiply the first numbers. The grams will cancel.
[tex]q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )[/tex]
Multiply again. This time the degrees Celsius cancel.
[tex]q= 56 \ J[/tex]
56 Joules of heat are needed.
