Answer:
[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
[tex]9\frac{3}{8} -8\frac{7}{8}[/tex]
Let's convert these to improper. To do this, we will multiply the denominator by the whole number and then add the numerator. The denominator will remain the same. We are just changing the numerator.[tex]9\frac{3}{8} =\frac{(8*9)+3}{8} =\frac{72+3}{8}= \frac{75}{8}\\8\frac{7}{8} =\frac{(8*8)+7}{8} =\frac{64+7}{8}= \frac{71}{8}[/tex]
Let's subtract:
[tex]\frac{75}{8} -\frac{71}{8} \\\\\frac{4}{8}[/tex]
[tex]\frac{4}{8}[/tex] can be reduced to [tex]\frac{1}{2}[/tex]
