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if the line 2x+3y=6 is perpendicular to the line ax+4y=3, then a=?​

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Answer:3y=−2x+12

y=(−2x+12)/3

y=-2x/3+4

m=-2/3

perpendicular -1/m=3/2

y=mx+c

y=3/2x+12

2y=3x+12

Step-by-step explanation:

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