A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface. (a) What type of charge distribution is inside the surface? a positively charged plane parallel to the end faces of the cylinder a positive line charge situated on and parallel to the axis of the cylinder a collection of positive point charges arranged in a line at the center of the cylinder and perpendicular to the axis of the cylinder a collection of negative point charges arranged in a line at the center of the cylinder and perpendicular to the axis of the cylinder a negatively charged plane parallel to the end faces of the cylinder (b) If the radius of the cylinder is 0.66 m and the magnitude of the electric field is 300 N/C, what is the net electric flux through the closed surface? How is the electric flux related to the electric field vector and the normal to the surface? What is the orientation of the electric field relative to the curved surface? N · m2/C (c) What is the net charge inside the cylinder?

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LUBLANAGO LUBLANAGO · Answer 1

Answer with Explanation:

a. Option d is true.

a negatively charged plane parallel to the end faces of the cylinder

b. Radius of cylinder, r=0.66m

Magnitude of electric field, E=300 N/C

We have to find the net flux through the closed surface.

Net electric flux,[tex]\phi=-2 EA=-2E(\pi r^2)[/tex]

[tex]\phi=-2\times 300\times (3.14\times (0.66)^2)[/tex]

[tex]\phi=-820.67 Nm^2/C[/tex]

c.

Net charge,[tex]Q=\epsilon_0\times \phi[/tex]

Where

[tex]\epsilon_0=8.85\times 10^{-12}[/tex]

[tex]Q=-820.67\times 8.85\times 10^{-12}[/tex]

[tex]Q=-7.26\times 10^{-9} C[/tex]

[tex]Q=-7.26nC[/tex]

Where [tex]1nC=10^{-9}C[/tex]