Answer:
t = 0.39 s
Explanation:
- Assuming that the ball is launched horizontally, once in the air, if we neglect the resistance of the air, the ball moves at a constant speed, equal to the initial velocity, in this case, 105.1 mi/hr.
- In order to find time in seconds, it is advisable to convert the speed in mi/hr to m/s, as follows:
[tex]105.1 mi/hr * (\frac{1hr}{3600s})*\frac{1609m}{1mi} = 47.0 m/s (1)[/tex]
- In the same way, it's advisable to convert 60' 6'' (60.5') to m, as follows:
[tex]60.5 ft * \frac{0.3058m}{1ft} = 18.5 m (2)[/tex]
- Applying the definition of average velocity, we can find the time traveled by the ball from pitcher's mound to home plate, as follows:
[tex]t = \frac{18.5m}{47m/s} = 0.39 s (3)[/tex]
