Answer :
Answer:
Step-by-step explanation:
[tex]d=vt-\frac{at^2}{2} \\ \\ a=\frac{2(d-vt)}{t^2} \\ \\ a=\frac{2(500-300(20)}{20^2} \\ \\ a=-27.5 \frac{m}{s^2}[/tex]
Answer:
Step-by-step explanation:
[tex]d=vt-\frac{at^2}{2} \\ \\ a=\frac{2(d-vt)}{t^2} \\ \\ a=\frac{2(500-300(20)}{20^2} \\ \\ a=-27.5 \frac{m}{s^2}[/tex]