A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a way that each player receives 13 cards, what is the probability that each player will receive three picture cards

Answer :

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = [tex]\frac{12!}{3! 3! 3! 3!}[/tex]

Now,

The Total number of ways in which Remaining cards are distributed = [tex]\frac{40!}{10! 10! 10! 10!}[/tex]

So,

Total number of ways of getting 3 picture card and remaining card = [tex]\frac{12!}{3! 3! 3! 3!}[/tex]× [tex]\frac{40!}{10! 10! 10! 10!}[/tex]

= [tex]\frac{12! 40!}{(3!)^{4} (10!)^{4} }[/tex]

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = [tex]\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }[/tex]

∴ The probability = [tex]\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}[/tex]

                            = [tex]\frac{12! 40!}{(3!)^{4} (10!)^{4} }[/tex]×[tex]\frac{(13!)^{4} }{ 52! }[/tex]

                           = [tex]\frac{12! 40!}{(3!)^{4} (10!)^{4} }[/tex]×[tex]\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }[/tex]

                           = [tex]\frac{12!}{(3!)^{4} }[/tex]×[tex]\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}[/tex]

                           = [tex]\frac{479,001,600}{(6)^{4} }[/tex]×[tex]\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}[/tex]

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

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