Which is equivalent to the square root

Step-by-step explanation:
[tex] { \sqrt[3]{8} }^{ \frac{1}{4}x } = {2}^{ \frac{1}{4} x} = {8}^{ \frac{1}{3} \times \frac{1}{4}x } \\ = {8}^{ \frac{1}{12} x} \\ = { \sqrt[12]{8} }^{x} [/tex]