[tex]x - \frac{3}{4} \geqslant - \frac{1}{8} [/tex]
[tex]x \geqslant - \frac{1}{8} + \frac{3}{4} [/tex]
Make both fractions to have same denominators by multiply 2 in 3/4 for both numerator and denominator.
[tex]x \geqslant - \frac{1}{8} + \frac{3 \times 2}{4 \times 2} \\ x \geqslant - \frac{ 1}{8} + \frac{6}{8} \\ x \geqslant \frac{5}{8} [/tex]
Hence, the solution is, "x is greater or equal to 5/8."
[tex] \large \boxed{x \geqslant \frac{5}{8} }[/tex]
