Answered

1.) What is the maximum number of grams of liquid water at 10C that can be heated to
30C by the addition of 84 joules of heat?

Answer :

Answer:

m = 1 gram

Explanation:

Given that,

Heat, Q = 84 J

The temperature increases from 10°C to 30°C.

We need to find maximum number of grams of liquid water. We know that the heat required is given by :

[tex]Q=mc\Delta T[/tex]

c is specific heat of water, c = 4,200 J/kg°C

Use the above formula to find m. So,

[tex]m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{84}{4,200\times (30-10)}\\\\m=0.001\ kg[/tex]

or

m = 1 gram

So, the required mass is 1 gram.

Go Question: Other Questions