Answer :
Answer:
Follows are the solution to this question:
Step-by-step explanation:
[tex]T: 1 \ R^n \to 1 \ R^n[/tex] is invertible lines transformation
[tex]S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \ \varepsilon\ 1 R^n\\\\[/tex]
T is invertiable linear transformation means that is
[tex]T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix[/tex]
and [tex]\ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists[/tex]
Let
[tex]V \varepsilon\ a\ R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v[/tex]
so,
[tex]s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n[/tex]