JUWERIA2005GO JUWERIA2005GO Chemistry Answered The emf of the cell:Ni/Ni^+2 (1.0 M) // Au^+3 (1.0 M)/ Au (E°= -0.25 V for Ni^+2/Ni; E°= 1.5 V for Au^+3/Au) is =A) 1.25vB) -1.25vC) 1.75vD) 2.0vplease help me