The overall enthalpy of the reaction has been obtained by reversing the second equation, and third equation must be halved. Thus, option D and E has been correct.
The complete reactions given in the question has been:
[tex]\rm C\;+\;O_2\;\rightarrow\;CO_2\\2\;CO\;+\;O_2\;\rightarrow\;2\;CO_2\\2\;H_2O\rightarrow\;2\;H_2\;+\;O_2[/tex]
The overall reaction has been:
[tex]\rm C\;+\;H_2O\;\rightarrow\;CO\;+\;H_2[/tex]
To obtain the overall enthalpy of the reaction, the intermediate reaction enthalpy has been arranged to give the overall equation.
The first equation has been in the correct sequence for the final reaction.
The second equation has been in in the same order to obtain the overall reaction. The CO has been the product, while carbon dioxide has been the reactant from equation 1. Thus, equation 2 has been reversed.
The third equation has 2 moles of water while the overall reaction has 1 mole of water. Thus, equation third has been halved.
Thus, to obtain the enthalpy of overall final reaction, the second equation must be reversed, and third equation must be halved. Thus, option D and E has been correct.
For more information about the enthalpy of reaction, refer to the link:
https://brainly.com/question/1657608
