Answer:
c ////
Step-by-step explanation:
C
[tex]x^2+6x-40=(x+10)(x-4)\\\\\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10} \\\frac{1}{x+10}*\frac{x-4}{x-4} \\\frac{x-4}{(x+10)(x-4)}+\frac{x-16}{(x+10)(x-4)} \\=\frac{2x-20}{(x+10)(x-4)}=\frac{2x-20}{x^2+6x-40}[/tex]
