Answer:
The solution of the system of equation is (3,8)
Step-by-step explanation:
We are given that
[tex]y=x+5[/tex]...(1)
[tex]y=2x+2[/tex]...(2)
We have to graph the system of linear equation.
For equation (1)
Substitute x=0
[tex]y=5[/tex]
Substitute y=0
[tex]x=-5[/tex]
Therefore, we obtained two points (0,5) and (-5,0) for equation (1).
For equation (2)
Substitute x=0
[tex]y=2[/tex]
Substitute y=0
[tex]2x=-2[/tex]
[tex]x=-1[/tex]
Therefore, we obtained two points (0,2) and (-1,0) for equation (2).
Now, we find intersection point of two equation
Substract equation (2) from (1)
[tex]x=3[/tex]
[tex]x=3[/tex]
Substitute x=3 in equation (1)
[tex]y=3+5=8[/tex]
The intersection point of two equation is at (3,8).
Hence, the solution of given system of equation is (3,8).
