Whats is the distance between the ferris wheel and the merry-go-round? Ferris wheel on the coordinate plane is (-9,6) and the location of the merry-go-round is (10,6)

Answer:
19 units
Step-by-step explanation:
use distance formula: d = [tex]\sqrt{(x_2-x_1)^{2}+(y_2+y_1)^{2}}[/tex]
x₂ = 10
x₁ = -1
y₂ = 6
y₁ = 6
now plug in
[tex]\sqrt{(10-(-9))^{2}+(6-6)^{2}}\\= \sqrt{19^{2}+0^{2}\\}\\= \sqrt{361}\\= 19[/tex]