Answer:
[tex]\sqrt{61}[/tex] units
Step-by-step explanation:
We are given that
[tex]P_1=(-2,5)[/tex]
[tex]P_2=(4,0)[/tex]
We have to find the distance d (P1, P2) between the points P, and P2
We know that
Distance between two points (x1,y1) and (x2,y2) i
=[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the formula
The distance d (P1, P2) between the points P, and P2
=[tex]\sqrt{(4-(-2))^2+(0-5)^2}[/tex]
The distance d (P1, P2) between the points P, and P2
[tex]=\sqrt{(4+2)^2+(-5)^2}[/tex]
The distance d (P1, P2) between the points P, and P2
=[tex]\sqrt{6^2+25}[/tex]
The distance d (P1, P2) between the points P, and P2
=[tex]\sqrt{61}[/tex] units
